Angry Birds Question in Physics Exam
By on July 10th, 2011

We have all come to love and have been playing the game on , , PSP, Desktop, Chrome and most recently Windows Phone 7 devices. In fact, we are also so crazy about it that we have been buying some cool Angry Birds merchandise as well.

As you can see, those tiny little birds have taken the world by storm and are in every nook or corner possible. In fact, there are even movies being made on them. So will this be the end? Apparently not. Some school decided to actually use Angry Birds as a question in their physics paper.

The question was no joke and could fetch students 7 marks. This is definitely something. Incidentally, there have also been other instances where teachers have used Angry Birds to teach physics to students.

angry_birds_physics

So  what will these Angry Birds invade next?

(via Reddit)

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  • http://dtechwiz.blogspot.com Karthik Prabhu

    Now that was something really interesting. :D People have really become addicted to this game. Simple concept, but a very addictive game.

  • http://meena-tech.blogspot.com/ Meena Bassem

    quite nice to have up-to-date teachers :D
    btw, if i had a question like that.it would be in the maths(dynamics) test , not the physics one.
    but really like the idea quite funny and not that difficult to solve

  • Eric Garza

    The sketched solution will slightly miss the target, the pig is 2m above the bird but the student is assuming they are at the same level.

  • Sanjevi

    This problem can be solved by using the theory of ‘projectile motion’, the formula is

    time(t) = velocity(v) x sin(angle)/g
    i.e. sin(angle) = v / t x g
    sin(angle)= 55.0 / 2.50 x 9.8
    sin(angle) = 0.8980
    angle = 63degree 54min ………….ans.

  • https://www.facebook.com/deep.nanuan Deep Singh Nanuan

    Horizontally :
    x = 55.0m
    Vix = 22.0 m/s
    ax = 0 m/s/s

    Vertically :
    y = (12-10) = 2 m
    Viy = 0 m/s = 22tanÆŸ
    ay = -9.8 m/s/s

    y=Viy*t+0.5*ay*t*t
    2=22tanÆŸ(2.5)+0.5*(-9.8)*2.5*2.5
    ÆŸ = (tan^-1)(32.625/55)
    ÆŸ = 30.68 degrees

  • http://www.facebook.com/profile.php?id=100002677480384 Adel Ansari

    My answer :D

    x= 55m , y= 2m and t= 2.50 s.
    Vx= V.Cos(angle)
    Vx=x / t => Vx=55/2.50 = 22 m.s^-1.
    y= (-1/2) × g t^2 + V t Because (angle).
    2=(-1/2) × 9.8 × 2.50^2 + 2.50 × ( Vx / Cos( angle) )× Sin( angle).
    2+30.625= 2.50 × 22 × tan( angle).
    tan( angle) = 32.625 / 55.
    tan( angle) = 0.59318.
    angle = tan^-1 ( 0.59318).
    angle = 30.67564743.

  • Adel Ansari

    My answer :D

    x= 55m , y= 2m and t= 2.50 s
    Vx= V.Cos(angle)
    Vx=x / t => Vx=55/2.50 = 22 m.s^-1
    y= (-1/2) × g t^2 + V t Cos (angle)
    2=(-1/2) × 9.8 × 2.50^2 + 2.50 × ( Vx / Cos( angle) )× Sin( angle)
    2+30.625= 2.50 × 22 × tan( angle)
    tan( angle) = 32.625 / 55
    tan( angle) = 0.59318
    angle = tan^-1 ( 0.59318)
    angle = 30.67564743

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